Six-Qubit Witness Is Hidden-Vertex Graph-Cut Representable¶
Claim/Theorem¶
Let f_{\mathcal S} be the 6-ary Boolean cut-rank function from [[six-qubit-witness-satisfies-direct-fsep.md]], equivalently from the stabilizer matrix
Write P=\{1,4,5\} and Q=\{2,3,6\}, and for x\in\{0,1\}^6 set
Then f_{\mathcal S} is expressible by binary submodular functions with auxiliary variables. More concretely, with hidden bits (a,b,c,d)\in\{0,1\}^4,
where
Every quadratic coefficient in E is nonpositive, so E is a binary submodular polynomial on the visible and hidden variables. Hence f_{\mathcal S}\in\langle \Gamma_{\mathrm{sub},2}\rangle, equivalently f_{\mathcal S} is ordinarily hidden-vertex graph-cut representable.
This is a derived explicit realization theorem.
-
By [[six-qubit-witness-satisfies-direct-fsep.md]], one already has the grouped formula
\[ f_{\mathcal S}(x) = \mathbf 1[p(x)\ge 1] + \mathbf 1[q(x)\ge 1] - \mathbf 1[p(x)\ge 1]\mathbf 1[q(x)=3] - \mathbf 1[p(x)=3]\mathbf 1[q(x)\ge 1]. \]Equivalently, if
\[ a_P:=\mathbf 1[p(x)\ge 1],\qquad c_P:=\mathbf 1[p(x)=3],\qquad b_Q:=\mathbf 1[q(x)\ge 1],\qquad d_Q:=\mathbf 1[q(x)=3], \]then
\[ f_{\mathcal S}(x)=a_P+b_Q-a_P d_Q-c_P b_Q. \] -
The energy
Erealizes exactly those threshold bits through pairwise penalties:ais the OR-threshold onP,cis the all-ones threshold onPwhenb=1,bis the OR-threshold onQ,dis the all-ones threshold onQwhena=1.
-
Grouping terms by the two triples gives
\[ E(x,a,b,c,d) = \underbrace{a+p(x)(1-a)+d(3-q(x)-a)}_{G_{p,q}(a,d)} + \underbrace{b+q(x)(1-b)+c(3-p(x)-b)}_{H_{p,q}(b,c)}. \]So minimization splits into two independent
2-bit problems:\[ \min_{a,d} G_{p,q}(a,d) + \min_{b,c} H_{p,q}(b,c). \] -
For fixed
p,q\in\{0,1,2,3\}, direct inspection gives\[ \min_{a,d} G_{p,q}(a,d)=\mathbf 1[p\ge 1\ \text{and}\ q<3], \]because
- if
q<3, thend=0is optimal and the remaining minimum is\min\{p,1\}=\mathbf 1[p\ge 1], - if
q=3, thena=1,d=1gives value0, and no negative value is possible.
- if
-
By symmetry,
\[ \min_{b,c} H_{p,q}(b,c)=\mathbf 1[q\ge 1\ \text{and}\ p<3]. \] -
Therefore
\[ \min_{a,b,c,d}E(x,a,b,c,d) = \mathbf 1[p\ge 1,\ q<3] + \mathbf 1[q\ge 1,\ p<3]. \]This equals
\[ \mathbf 1[p\ge 1]+\mathbf 1[q\ge 1]-\mathbf 1[p\ge 1]\mathbf 1[q=3]-\mathbf 1[p=3]\mathbf 1[q\ge 1] = f_{\mathcal S}(x), \]which proves the realization.
Consequences for the current frontier:
- the
6-qubit witness from [[six-qubit-stabilizer-cut-rank-escapes-modular-plus-fan-cone.md]] is not a counterexample to ordinary hidden-vertex graph-cut representability; - the fan-cone obstruction and the direct
F_{\mathrm{sep}}pass from [[six-qubit-witness-satisfies-direct-fsep.md]] are now reconciled by an explicit four-hidden-bit realization; - any negative theorem must therefore look beyond this witness, while any positive theorem beyond the fan cone can use this node as the first genuine arity-
6realization template.
Dependencies¶
- [[six-qubit-witness-satisfies-direct-fsep.md]]
- [[six-qubit-stabilizer-cut-rank-escapes-modular-plus-fan-cone.md]]
- [[cross-cut-stabilizer-rank-rank-formula.md]]
Conflicts/Gaps¶
- This node is witness-specific. It does not prove that all
6-qubit stabilizer cut-rank functions are hidden-vertex graph-cut representable. - The realization is derived by explicit construction, not quoted verbatim from the cited papers.
- Hidden-vertex representability still does not by itself yield a routing-style
CD(T_n,G)interpretation on the physical qubit set.
Sources¶
10.1016/j.dam.2009.07.00110.48550/arXiv.2109.14599