Pinned Five-Ary Shadows Of M222 Obstruct One-Hidden Realizability¶
Claim/Theorem¶
Let M_{2,2,2} be the smallest connected member of the multi-parallel-circuit family from [[multiple-parallel-classes-on-one-circuit-give-connected-cut-rank-at-least-three-family.md]], and write
Consider 5-ary pinning minors of f_{2,2,2} obtained by keeping any 5 visible coordinates and fixing the remaining 2 to constants in {0,1}.
Then the first exact low-auxiliary obstruction already appears on these genuinely global shadows:
-
up to permutation of the
5visible coordinates, the84pinned5-ary minors collapse to10canonical truth tables; -
exactly
7of these10canonical classes are not representable by a quadratic binary-submodular energy with one auxiliary bit; -
consequently
f_{2,2,2}itself is not representable with one auxiliary bit.In particular, the representative pinned shadow obtained by keeping
\[ (u,a_1,b_1,a_2,b_2) \]and pinning
\[ (a_3,b_3)=(0,0) \]has no one-hidden-bit realization.
Equivalently: the first exact low-auxiliary obstruction for
M_{2,2,2}appears already on pinned5-ary shadows, even though [[every-four-ary-pinning-minor-of-m222-is-one-hidden-representable.md]] shows that every pinned4-ary shadow is still one-hidden representable.
This is a derived exact finite theorem.
-
By [[multiple-parallel-classes-on-one-circuit-give-connected-cut-rank-at-least-three-family.md]],
f_{2,2,2}is the7-ary cut-rank function of the first connected\chi\ge 3test family. -
A quadratic pseudo-Boolean energy with one hidden bit has the form
\[ E(y,h)=q(y)+h\,\ell(y), \]where
qis quadratic in the visible coordinates and\ellis affine. Minimizing overhgives\[ \min_{h\in\{0,1\}}E(y,h)=q(y)+\min(0,\ell(y)). \]So one-hidden representability is equivalent to existence of a quadratic visible part
qand an affine negative-branch mask\[ B=\{y\in\{0,1\}^5:\ell(y)<0\}. \] -
Any strict affine threshold subset of
\{0,1\}^5has an integer witnessing affine form\[ \ell(y)=\lambda_0+\sum_{i=1}^5 \lambda_i y_i \]with
\[ |\lambda_i|\le 216 \]for all
i, and with\[ \ell(y)\le -1 \ \text{on } B, \qquad \ell(y)\ge 0 \ \text{off } B. \]Indeed, after scaling any strict separator to margin
1, choose a basic feasible solution of the resulting linear system. It is determined by6tight inequalities in the6affine coefficients. The corresponding6\times 6matrix has entries in{0,\pm 1}, so Hadamard gives determinant at most\[ 6^{6/2}=216. \]Cramer's rule then yields an integer witness with the stated coordinate bound.
-
For any pinned
5-ary shadowg, this turns one-hidden representability into an exact MILP with:16continuous coefficients for the quadratic visible partq,6integer affine coefficients\lambda_0,\dots,\lambda_5in[-216,216],32branch binaries selecting whether each visible assignment lies inB.
The visible quadratic coefficients are constrained by
\beta_{ij}\le 0, and the hidden-visible coefficients by\lambda_i\le 0fori\ge 1. -
Since every pinned
5-ary shadow takes values in{0,1,2,3}, and every affine witness from step3satisfies\[ |\ell(y)|\le 6\cdot 216=1296, \]one has
\[ |q(y)|\le 1299. \]By Möbius inversion on the
5-cube, every coefficient ofqis therefore bounded in absolute value by\[ 32\cdot 1299 = 41568. \]Hence the resulting MILP is exact.
-
There are
\[ \binom{7}{5}\cdot 2^2 = 84 \]pinned
5-ary minors off_{2,2,2}. -
Up to permutation of the
5visible coordinates, these84minors collapse to10canonical truth tables. -
Solving the exact one-hidden MILP for each canonical class yields:
3feasible classes,7infeasible classes.
So one-hidden representability already fails on pinned
5-ary shadows. -
For the representative shadow with visible coordinates
(u,a_1,b_1,a_2,b_2)and pinned(a_3,b_3)=(0,0), the explicit formula is\[ g(u,a_1,b_1,a_2,b_2) = \mathbf 1[a_1\ne b_1] +\mathbf 1[a_2\ne b_2] +u +(1-u)\,\mathbf 1[(a_1,b_1)=(1,1)\ \vee\ (a_2,b_2)=(1,1)]. \]Its exact one-hidden MILP is infeasible.
-
If
f_{2,2,2}had a one-hidden realization, then every pinned minor would inherit one by fixing visible coordinates in that same gadget. Therefore infeasibility of any pinned5-ary shadow proves thatf_{2,2,2}itself has no one-hidden realization.
Consequences for the current frontier:
- the exact one-hidden boundary is now pinned down:
4-ary pinning shadows are all positive, but5-ary pinning shadows already contain obstructions; - this is an unbounded
k<=1impossibility theorem forM_{2,2,2}, not a coefficient-box search artifact; - the case of
2hidden bits remains open, as does a fully less-symmetrick>=3realization of the full connected witness.
Dependencies¶
- [[every-four-ary-pinning-minor-of-m222-is-one-hidden-representable.md]]
- [[multiple-parallel-classes-on-one-circuit-give-connected-cut-rank-at-least-three-family.md]]
- [[smallest-connected-multi-parallel-circuit-member-has-no-1-or-2-auxiliary-realization-in-large-coefficient-box.md]]
Conflicts/Gaps¶
- This node proves only an unbounded
k<=1impossibility theorem forM_{2,2,2}. - It does not settle whether some pinned
5-ary shadow, orf_{2,2,2}itself, is representable with2hidden bits. - It also does not rule out a fully less-symmetric realization with
3or more hidden bits. - Even a future whole-family positive or negative theorem would still need a separate bridge to routing-style
CD(T_n,G)semantics.
Sources¶
10.1016/j.dam.2009.07.00110.48550/arXiv.2109.14599